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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q45-Q50):
NEW QUESTION # 45
The graph shows the number of user accounts on a social media website over time.
When did the number of user accounts reach 4,500?
- A. After 2.0months
- B. After 3.2months
- C. After 8.8months
- D. After 7.0months
Answer: A
Explanation:
The graph represents the number of user accounts over time.
The horizontal axis represents:
" Time in months "
The vertical axis represents:
" Number of user accounts "
We need to find when the number of user accounts reached:
4,500
On the vertical axis, 4,500is halfway between:
3,000
and
6,000
So we look for the point where the blue curve reaches that height.
From the graph, the curve reaches approximately 4,500user accounts at:
x#2.0
That means the website had about 4,500user accounts after approximately:
2.0 " months "
NEW QUESTION # 46
In the graph showing the number of daily homework problems assigned for a math class, the horizontal axis shows the number of school days since the beginning of the term and the vertical axis shows the number of daily homework problems.
Which conclusion is correct based on this graph?
- A. The maximum number of daily homework problems is 29 and occurs at day 3.
- B. The maximum number of daily homework problems is 21 and occurs at day 11.
- C. The minimum number of daily homework problems is 18 and occurs at day 22.
- D. The minimum number of daily homework problems is 31 and occurs at day 1.
Answer: C
Explanation:
This question asks us to identify a correct conclusion from the graph.
The vertical axis represents:
" number of daily homework problems "
The horizontal axis represents:
" school days since the beginning of the term "
From the graph, the lowest point occurs at the far right, around:
" day " 22
The corresponding number of homework problems is approximately:
18
So the minimum number of daily homework problems is 18, and it occurs at day 22.
Therefore, the correct answer is:
# ( " D " )
NEW QUESTION # 47
Consider the graph of p(t)shown. The function represents the number of active players, p, in a game thours after 11:00 a.m.
Which interpretation of the concavity between t=0.4and t=3.6is correct?
- A. The number of players is increasing faster and faster.
- B. The number of players is decreasing slower and slower.
- C. The number of players is increasing slower and slower.
- D. The number of players is decreasing faster and faster.
Answer: C
Explanation:
The graph represents:
p(t)= " number of active players "
where:
t= " hours after 11:00 a.m. "
We need to interpret the concavity between:
t=0.4
and
t=3.6
On this interval, the graph is rising, so the number of players is increasing.
But as the graph rises, it begins to level off near the top. This means the rate of increase is getting smaller.
So the number of players is not increasing faster and faster. Instead, it is increasing, but more slowly as time passes.
That means the graph is concave down on this interval.
The correct interpretation is:
" The number of players is increasing slower and slower. "
NEW QUESTION # 48
A vehicle is traveling away from a town at a fixed rate. After 1 hours, the vehicle is 200 miles from the town.
After 4 hours, the vehicle is 395 miles from the town.
Which function represents the distance, d, between the vehicle and the town after thours?
- A. d(t)=135t
- B. d(t)=135t+65
- C. d(t)=65t+135
- D. d(t)=65t
Answer: C
Explanation:
Because the vehicle is traveling away from the town at a fixed rate, the distance can be modeled by a linear function:
d(t)=mt+b
where:
m= " rate of change "
and
b= " initial distance from the town "
We are given two points:
(1#200)
and
(4#395)
These mean:
After 1hour, the vehicle is 200miles away.
After 4hours, the vehicle is 395miles away.
First, find the rate of change:
m=(395-200)/(4-1)
m=195/3
m=65
So the vehicle is moving away from the town at a rate of:
65 " miles per hour "
Now the function has the form:
d(t)=65t+b
Use the point (1#200)to find b:
200=65(1)+b
200=65+b
b=135
Therefore, the function is:
d(t)=65t+135
Check using t=4:
d(4)=65(4)+135
d(4)=260+135
d(4)=395
NEW QUESTION # 49
An exponential growth function can be used to model the number of bacteria in a population. The function G(t)=1,600× # 1.31 #